In an orthogonal cutting operation, shear angle = 11.31O, cutting force = 900 N and thrustforce =…

In an orthogonal cutting operation, shear angle = 11.31O, cutting force = 900 N and thrustforce = 810N. Then the shear force will be approximately (given sin11.31O = 0.2).Consider the following reasons for using non-conventional machining processes:(i) High-strength alloys(ii) Complex surfaces(iii) High accuracies and surface finishWhich of the above are correct?