What is the axial force, shear force
Calculate the axial force, shear force and internal actions of the following questions 1 to 6
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What is the axial force, shear force and moment at C in the beam below.Answer: NC =0kN; VC =+6kN; MC =+36kN.m3mE12m24kN3mAC3mDBDetermine the axial force, shear force and moment at B in the beam below.Answer: NB = 0 kN; VB = +6 kN; MB = +18 kN.mE12m24kN3mAB3mDC3mDetermine the axial force, shear force and moment at B in the beam below.Answer: NB = +18 kN; VB = +6 kN; MB = +18 kN.m30kN3543m3mBDCA12mEDetermine the axial force, shear force and moment at B in the beam below.Answer: NB = 0 kN; VB = +6 kN; MB = +18 kN.mWhat is the axial force in DE? Answer: -18kN (compression).35430kN3m3mBDCA12mEDetermine the internal actions in the beam shown below at a cut just to the right of support A. (Support reactions at pin and roller supports are concentrated loads.)Answer: NA+ = 0kN; VA+ = +6kN; MA+ = 0kN.mE12m24kNAC3mDBDetermine the internal actions in the beam shown below at a cut just to the left and just to the right of B. Answer: NB- = 0kN; VB- = +10kN; MB- = +30kN.mNB+ = 0kN; VB+ = +2kN; MB+ = +30kN.m16kN8kNE12mAC3mDB3m
What is the axial force, shear force and moment at C in the beam below.Answer: NC =0kN; VC =+6kN; MC =+36kN.m3mE12m24kN3mAC3mDBDetermine the axial force, shear force and moment at B in the beam below.Answer: NB = 0 kN; VB = +6 kN; MB = +18 kN.mE12m24kN3mAB3mDC3mDetermine the axial force, shear force and moment at B in the beam below.Answer: NB = +18 kN; VB = +6 kN; MB = +18 kN.m30kN3543m3mBDCA12mEDetermine the axial force, shear force and moment at B in the beam below.Answer: NB = 0 kN; VB = +6 kN; MB = +18 kN.mWhat is the axial force in DE? Answer: -18kN (compression).35430kN3m3mBDCA12mEDetermine the internal actions in the beam shown below at a cut just to the right of support A. (Support reactions at pin and roller supports are concentrated loads.)Answer: NA+ = 0kN; VA+ = +6kN; MA+ = 0kN.mE12m24kNAC3mDBDetermine the internal actions in the beam shown below at a cut just to the left and just to the right of B. Answer: NB- = 0kN; VB- = +10kN; MB- = +30kN.mNB+ = 0kN; VB+ = +2kN; MB+ = +30kN.m16kN8kNE12mAC3mDB3m
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